# A projectile is projected with a speed u at an angle θ with the horizontal. What is the speed when its direction of motion makes an angle θ/2 with the horizontal

(ucos2θ)/2

ucosθ

u(2cosθ−secθ)

u(cosθ−secθ)

## The correct Answer is:C

## vcosθ=ucos2θ

v=(u2cos2θ−1cosθ)=u[2cosθ−secθ]

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